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Home/ Questions/Q 7904169
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T09:56:19+00:00 2026-06-03T09:56:19+00:00

I have the next array: var Images = $(‘.cs_slider’).children(); Checked the array and it

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I have the next array:

var Images = $('.cs_slider').children();

Checked the array and it is not empty.

The array contains divs, each one of them, has another div inside it.

I would like to use fadeOut() on the inside div (.info) of the next image that slides.

I tried using this, but it doesn’t work (Started with JQuery a month ago):

Images[CurrentImage].('.info').fadeOut();

CurrentImage is surely an integer.

The effect should run only once, so looping is not what I meant. Any ideas what’s wrong with it?

Thanks!

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  1. Editorial Team
    Editorial Team
    2026-06-03T09:56:20+00:00Added an answer on June 3, 2026 at 9:56 am

    Try this:

    $('.info', Images[CurrentImage]).fadeOut();
    

    which is equivalent to:

    $(Images[CurrentImage]).find('.info').fadeOut();
    

    Note that Images[CurrentImage]1 is a DOM element, not a jQuery object.


    1 NB: those are bad variable names – upper case is normally reserved for classes

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