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Home/ Questions/Q 8121443
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T05:29:23+00:00 2026-06-06T05:29:23+00:00

I have the next code: class Printer{ Activity activity; public Printer (Activity activity) {

  • 0

I have the next code:

class Printer{
Activity activity;
public Printer (Activity activity) {
    this.activity = activity;
    initializeBluetooth();
}

public boolean initializeBluetooth() {
    BluetoothAdapter mBluetoothAdapter = BluetoothAdapter.getDefaultAdapter();
    if (mBluetoothAdapter == null) {
        Context context = activity.getApplicationContext();
        Toast toast = Toast.makeText(context, activity.getString(R.string.notSupportedBluetooth), 3000);
        toast.show();
        return false;
    } else {
        if (!mBluetoothAdapter.isEnabled()) {
            Intent enableBtIntent = new Intent(BluetoothAdapter.ACTION_REQUEST_ENABLE);
            activity.startActivityForResult(enableBtIntent, 0);
            return false;
        }
    }
    return true;
}

protected void onActivityResult(int requestCode, int resultCode, Intent intent) {
    System.out.println(resultCode);
    if (resultCode == 0) {
        System.out.println("one");
    } else {
        System.out.println("two");
    }
}}

The problem is the onActivityResult, i know it can not be called because the class is not an Activity, so how can i check if the user clicked yes or no to the bluetooth request with out turning my class to an activity??? activity.startActivityForResult(enableBtIntent, 0);
Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T05:29:24+00:00Added an answer on June 6, 2026 at 5:29 am

    Why are you doing this? Just include all of the bluetooth functionality in the Activity class… there is no need to create a separate class for this.

    Anyway, just copy and paste your onActivityResult code into your Activity file:

    protected void onActivityResult(int requestCode, int resultCode, Intent intent) {
        System.out.println(resultCode);
        if (resultCode == 0) {
            System.out.println("one");
        } else {
            System.out.println("two");
        }
    }
    

    It makes no sense to include onActivityResult in your Printer class, as onActivityResult will be called for the calling Activity.

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