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Home/ Questions/Q 4000030
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T07:43:53+00:00 2026-05-20T07:43:53+00:00

I have the next command-line option which I need to split in a name-value

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I have the next command-line option which I need to split in a name-value format:

-table tab -delimiter "," -limit:10

The regexp construction is:

(?<=[-{1,2}|/])(?<name>[a-zA-Z0-9_]*)[ |:|"]*(?<value>[0-9A-Za-z.?=&\|+ :'*(),\\]*)(?=[ |"]|$)

My problem is in the delimiter option, when I put -delimiter "|" or -delimiter ":", the regexp construction doesn’t work in spite I included these characters, in those cases: name=delimiter, but value is equal to empty, why?

Thanks for your help.

Edit:
Tim and Gabe, thanks for your help.
The final construction that works is:

(?<=-{1,2}|/)(?<name>[a-zA-Z0-9_]*)\s*:?\s*"? *(?<value>[0-9A-Za-z.?=&\|+ :'*(),\\]*)(?=[ "]|$)
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  1. Editorial Team
    Editorial Team
    2026-05-20T07:43:53+00:00Added an answer on May 20, 2026 at 7:43 am

    Your problem is in [ |:|"]* — it appears as though you think | means “or” within brackets even though you clearly don’t use it in the next set of brackets.

    You just want [ :"]* probably, which would make "|" work. Unfortunately that group matches any number of characters that can be a space, colon, or quote, which means ":" is all considered to be part of the space between the name and value. You will need to better define your allowed set of characters between the name and value.

    I suggest: \s*:?\s*"? (any amount of space, followed by an optional colon, followed by any amount of space, followed by an optional quote).

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