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Editorial Team
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Asked: 2026-06-14T13:33:26+00:00

I have the program unzipping the file to %temp%\myfolder\ I need to run a

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I have the program unzipping the file to %temp%\myfolder\

I need to run a file from within that location.
I have tried both shell and process.start but ultimately I’m looking for:

Process.start("%temp%\myfolder\start.cmd")

Also I looked on msdn on the getenvironmentvariable but nothing has worked. 🙁

Update: This is what I have in a nutshell

Imports system.diagnostics
Imports system.IO

System.Environment.GetEnvironmentVariable("TEMP")
Dim temp As String = System.IO.Path.GetTempPath

Things I have tried
process.start("%temp%\myfolder\start.cmd")
process.start("temp" & "myfolder\start.cmd")

I get an error code saying “file not found”. But if I copy %temp%\myfolder\start.cmd into run or cmd.exe the program runs.

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1 Answer

  1. Editorial Team

    First set the 

    Environment.CurrentDirectory = Environment.GetEnvironmentVariable("temp")
' Possible variables include temp, tmp, and windir for examples.

    This command will place the current directory as C:\Users\ (currentuser)\appdata\local\temp or which ever the variable is set for. Then run process start. It should look like this:

    Environment.CurrentDirectory = Environment.GetEnvironmentVariable("temp")
Process.start("myfolder\start.cmd")
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