Question

i have the same json string twice but the second time i get an error.

{"data":[{"ServerID":"1","UserID":"3","Name":"salzig","State_since":"2012-11-23T23:16:27.458000000","State":"saved","UUID":"Hardware   85f5d278-f6d6-49c2-87e7-c249d8002897"}],"error":[null,null,null]} devcontrol.js:8

{"data":[{"ServerID":"1","UserID":"3","Name":"salzig","State_since":"2012-11-23T23:16:27.458000000","State":"saved","UUID":"Hardware   85f5d278-f6d6-49c2-87e7-c249d8002897"}],"error":[null,null,null]} devcontrol.js:8

Uncaught TypeError: Object function (E,F)} has no method ‘parseJSON’ devcontrol.js:9

my code line devcontrol.js 8 and 9:

console.log(data);
data = $.parseJSON(data);

how can that be.

update
i now made a console.log($) evry trime bevor he trys to convert the string into a json and got

undefined

it turnd out the secounde time it’s undefined.
i managed to found out it was because of zfdebug they used document ready and then asked about jquery noconfilect thats why $ was undifend the secound time

Answer 1

Uncaught TypeError: Object function (E,F)} has no method 'parseJSON' devcontrol.js:9

Is telling you that the object you’re referencing with the $ variable has no method called that. This could be caused by a few things.

• You’re using an old version that doesn’t support this function. parseJSON was introduced in version 1.4.1. Either update your version, or use the native JSON.parse() method.
• Your script link to jQuery is wrong. Checked the page loaded the source script with a 200 success
• Another library is taking the $ variable after jquery has defined it. You can disassociate jQuery from the $ variable using jQuery.noConflict(), reassign to anothe variable like $$, or just using jQuery.parseJSON()
• You have scripts running before the page is fully loaded. Make sure every is run within $(document).ready(function () { /*your code here*/ });