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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T23:01:20+00:00 2026-05-13T23:01:20+00:00

I have the same question as #1895500 , but with PostgreSQL not MySQL. How

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I have the same question as #1895500, but with PostgreSQL not MySQL.

How can I define a view that has a calculated field, for example:

 (mytable.col1 * 2) AS times_two

… and create another calculated field that’s based on the first one:

 (times_two * 2) AS times_four

…?

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  1. Editorial Team
    Editorial Team
    2026-05-13T23:01:21+00:00Added an answer on May 13, 2026 at 11:01 pm

    Depending on how heavy the formla is, you could use a subquery:

    select inner.*, times_two * 2 from
    (select mycol * 2 as times_two from table) sub
    

    Or rewrite the computation:

    select mycol * 2, mycol * 2 * 2 from table
    
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