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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T00:11:04+00:00 2026-05-15T00:11:04+00:00

I have the simplest problem to implement, but so far I have not been

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I have the simplest problem to implement, but so far I have not been able to get my head around a solution in Python.

I have built a table that looks similar to this one:

501 - ASIA
1262 - EUROPE
3389 - LATAM
5409 - US

I will test a certain value to see if it falls within these ranges, 389 -> ASIA, 1300 -> LATAM, 5400 -> US. A value greater than 5409 should not return a lookup value.

I normally have a one to one match, and would implement a dictionary for the lookup.

But in this case I have to consider these ranges, and I am not seeing my way out of the problem.

Maybe without providing the whole solution, could you provide some comments that would help me look in the right direction?

It is very similar to a vlookup in a spreadsheet.

I would describe my Python knowledge as somewhere in between basic to intermediate.

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  1. Editorial Team
    Editorial Team
    2026-05-15T00:11:04+00:00Added an answer on May 15, 2026 at 12:11 am

    You could use the bisect module. Instead of linear search, that would use binary search, which would hopefully be faster:

    import bisect
    
    places = [
        (501, 'ASIA'),
        (1262, 'EUROPE'),
        (3389, 'LATAM'),
        (5409, 'US'),
    ]
    places.sort() # list must be sorted
    
    for to_find in (389, 1300, 5400):
        pos = bisect.bisect_right(places, (to_find,))
        print '%s -> %s' % (to_find, places[pos])
    

    Will print:

    389 -> (501, 'ASIA')
    1300 -> (3389, 'LATAM')
    5400 -> (5409, 'US')
    
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