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Home/ Questions/Q 3751898
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T09:08:22+00:00 2026-05-19T09:08:22+00:00

I have the SQL query: select title, scale / next_scale, c from ( select

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I have the SQL query:

select title, scale / next_scale, c
from ( select title, scale, scale*D0 AS c, 
              lead(scale) over(partition by title order by scale asc) as next_scale,
              row_number() over(partition by title order by scale asc) as agg_row
       from signatures
     ) agg
where agg_row = 1;

and it works as expected. However, what I really want the sorting “scale” value to be an arithmetic operation between several columns, so I tried using an AS clause (shown above) and modify the query to:

select title, scale / next_scale, c
from ( select title, scale, scale*D0 AS c, 
              lead(scale) over(partition by title order by c asc) as next_scale,
              row_number() over(partition by title order by c asc) as agg_row
       from signatures
     ) agg
where agg_row = 1;

However, it fails at the ORDER BY c. Why is this? I can substitute ORDER BY scale*D0 and it works just fine. However, I will eventually want to use a term like: scale*D0*D1*D2*...*D100; and I don’t want to have to calculate that 3 different times – not to mention the physical length of the query. I am hoping to have scale*D0*D1*D2*...*D100 AS c and then ORDER BY c.

Is this possible?

I am using PostgreSQL.

Many thanks,
Brett

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  1. Editorial Team
    Editorial Team
    2026-05-19T09:08:22+00:00Added an answer on May 19, 2026 at 9:08 am

    Calculate c in a subquery:

    select title, scale / next_scale, c
    from ( select title, scale, c, 
                  lead(scale) over(partition by title order by c asc) as next_scale,
                  row_number() over(partition by title order by c asc) as agg_row
           from (select title, scale, scale * D0 AS c from signatures) signatures_calc
         ) agg
    where agg_row = 1;
    
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