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Home/ Questions/Q 3391302
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T03:47:20+00:00 2026-05-18T03:47:20+00:00

i have the xml in a structure such as this: <RWFCriteria reportType=ProgramReview> <item id=36

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i have the xml in a structure such as this:

<RWFCriteria reportType="ProgramReview">
  <item id="36" name="" value="9" type="Milestone" />
  <item id="31" name="" value="9" type="Milestone" />
  <item id="33" name="" value="11" type="Milestone" />
</RWFCriteria>

and need to it be converted to:

<data>
  <release id="9">  <milestone id="36" /> <milestone id="31" /> </release>
  <release id="11"> <milestone id="33" /> </release>
</data>

what would the XSLT look like for this transformation?

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  1. Editorial Team
    Editorial Team
    2026-05-18T03:47:21+00:00Added an answer on May 18, 2026 at 3:47 am

    You need to group the items based on their value attribute. If you are using xslt 1 you can do this using the Muenchian Method which would look something like:

      <xsl:key name="item-value" match="item" use="@value" />
    
      <xsl:template match="/RWFCriteria">
    
        <data>
          <xsl:for-each select="item[count(. | key('item-value', @value)[1]) = 1]">
            <release id="{@value}">
              <xsl:for-each select="key('item-value', @value)">
                <milestone id="{@id}" />
              </xsl:for-each>
            </release>
          </xsl:for-each>
        </data>
    
      </xsl:template>
    
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