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Home/ Questions/Q 8486317
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T20:54:41+00:00 2026-06-10T20:54:41+00:00

i have these classes class SuperParent { @Override public String toString() { return SuperParent;

  • 0

i have these classes

class SuperParent {
        @Override
        public String toString() {

            return "SuperParent";
        }
    }

    class A extends SuperParent {

        @Override
        public String toString() {

            return "A";
        }
    }

    class B extends SuperParent {

        @Override
        public String toString() {

            return "B";
        }

    }

and i want to have a List of ArrayLists , so i can add to ArrayList of B’s and A’s
i tried

List<ArrayList<?extends SuperParent>> mList = new ArrayList<ArrayList<SuperParent>>();

but does not compile

when i tried this,

ArrayList<ArrayList<SuperParent>> mList = new ArrayList<SuperParent>>();

it compiles but i cant add ArrayLists of As or ArrayLists Bs

i understand java types and inheritance too but when it comes to Generics i miss with it .
Any reference or a declaration would help me .

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T20:54:43+00:00Added an answer on June 10, 2026 at 8:54 pm

    This is how you would declare a list of lists where the elements of outer list can be a list of A or list of B:

    ArrayList<ArrayList<? extends SuperParent>> lists = 
        new ArrayList<ArrayList<? extends SuperParent>>();
    lists.add(new ArrayList<A>(Arrays.asList(new A(), new A())));
    lists.add(new ArrayList<B>(Arrays.asList(new B(), new B())));
    

    Generally, it is recommended to use interface types than concrete types when declaring or accepting as method parameters. That way, the above snippet would look like below:

    List<List<? extends SuperParent>> lists = 
        new ArrayList<List<? extends SuperParent>>();
    lists.add(Arrays.asList(new A(), new A()));
    lists.add(Arrays.asList(new B(), new B()));
    
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