Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1005391
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T08:17:14+00:00 2026-05-16T08:17:14+00:00

I have these tables: USER TABLE uid | name | role | | 1

  • 0

I have these tables:

USER TABLE
uid | name | role
    |      |
1   | bob  | package 1
2   | jill | package 2
3   | pam  | package 1

NODE TABLE
nid | uid | type
    |     |
1   | 1   | car
2   | 1   | car
3   | 1   | car
4   | 2   | page
5   | 1   | car
6   | 3   | car

If I do:

select u.uid, u.name, count(nid) as totalNodes from USER as u left join NODE on n.uid = u.uid where n.type = 'car' group by u.uid

I end up with:

uid | name | totalNodes
    |      | 
1   | bob  | 4
3   | pam  | 1

In other words, Jill is excluded. Why? And how can I avoid this? I.e. I want Jill to also appear in the list, but with totalNodes as 0 (or even NULL).

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T08:17:14+00:00Added an answer on May 16, 2026 at 8:17 am

    You need to perform your aggregate before attempting to join the tables as what you are currently doing is left joining, then restricting the data (at which point Jill is excluded) then grouping. If you do the count and restriction in a subquery you can then left join these results to the user table for the output you want:

    SELECT u.uid, u.name, IFNULL(c.nodecount,0) AS `count`
    FROM USER u LEFT JOIN (
        SELECT uid, `type` , COUNT(nid) AS nodecount
        FROM node
        WHERE TYPE = 'car'
        GROUP BY uid, type
    ) AS c ON u.uid = c.uid
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.