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Home/ Questions/Q 7642029
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T09:05:06+00:00 2026-05-31T09:05:06+00:00

I have this array Array *array = [@string1, @string2, @string3, @string4]; I want to

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I have this array Array *array = [@"string1", @"string2", @"string3", @"string4"];

I want to get each string object and assign to dynamically created NSString objects.

Is it possible?

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  1. Editorial Team
    Editorial Team
    2026-05-31T09:05:07+00:00Added an answer on May 31, 2026 at 9:05 am

    I’m not quite sure what you are asking for.

    You can have something like this:

    typedef struct Array_s {
       __strong id *values;
       int count;
    } Array;
    
    #define array(values) ({ id _v[] = { values }; int _c = sizeof(_v) * sizeof(*_v); int *_cpy = malloc(sizeof(id) * _c); memcpy(_cpy, _v, sizeof(id) * _c); Array _a; _a.count = _c; _a.values = _cpy; _a; })
    
    #define destroy(array) ({ free(array->values); })
    

    And you can use this like this:

    Array a = array(@"This", @"Is", @"A", @"Test");
    
    for (int i = 0; i < a.count; i++)
    {
        NSLog(@"%@", a.values[i]);
    }
    
    destroy(a);
    

    EDIT: It appears I read your question wrong.

    NSArray *deepCopyArray(NSArray *input)
    {
        id copiedValues[input.count];
    
        for (int i = 0; i < input.count; i++)
        {
            copiedValues[i] = [[input objectAtIndex:i] copy];
        }
    
        return [NSArray arrayWithObjects:copiedValues count:input.count];
    }
    
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