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Home/ Questions/Q 6921333
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:15:49+00:00 2026-05-27T10:15:49+00:00

I have this base class having the following interface: abstract class Base { abstract

  • 0

I have this base class having the following interface:

abstract class Base
{
  abstract public object Val
  {
    get;
  }
}

For any derived classes, Val‘s value must be specified at object creation time.
The question is: How can I make a derived class do this (hopefully at compile time)?
I tried adding a constructor:

abstract class Base
{
  public Base(object value)
  {
    val = value;
  }

  private object val;

  ...
}

But as you can see then I had to declare a private field to store value in it (because Value is read-only).
The problem arises because I want to add some kind of effect to derived classes using the Decorator/Wrapper pattern introduced in GoF Design Patterns. But because I have declared the field inside Base class, the decorators keep saving a copy of the same data and I end up wasting memory.

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:15:50+00:00Added an answer on May 27, 2026 at 10:15 am

    Try this instead:

    abstract class Base 
    {
        public Base(object val)
        {
            this.Val = val;
        }
    
        public object Val { get; private set; }
    }
    

    That way, your derived class doesn’t need its own field:

    public class Derived : Base
    {
        public Derived(object val) : base(val) { }
    }
    
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