Question

I have this block of code:

 while IFS=$'\n' read -r line || [[ -n "$line" ]]; do
    if [ "$line" != "" ]; then
        echo -e "$lanIP\t$line" >> /tmp/ipList;
    fi
done < "/tmp/includeList"

I know this must be really simple. But I have another list (/tmp/excludeList). I only want to echo the line within my while loop if the line ins’t found in my excludeList. How do I do that. Is there some awk statement or something?

Answer 1

use grep

while IFS=$'\n' read -r line || [[ -n "$line" ]]; do
    if [[ -n ${line} ]] \
        && ! grep -xF "$line" excludefile &>/dev/null; then
       echo -e "$lanIP\t$line" >> /tmp/ipList;
    fi
done < "/tmp/includeList"

the -n $line means if $line is not empty
the grep returns true if $line is found in exclude file which is inverted by the ! so returns true if the line is not found.
-x means line matched so nothing else can appear on the line
-F means fixed string so if any metacharacters end up in $line they’ll be matched literally.

Hope this helps