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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T21:22:18+00:00 2026-05-15T21:22:18+00:00

I have this code: $a = array (‘zero’,’one’,’two’, ‘three’); foreach ($a as &$v) {

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I have this code:

$a = array ('zero','one','two', 'three');

foreach ($a as &$v) {

}

foreach ($a as $v) {
  echo $v.PHP_EOL;
}

Can somebody explain why the output is:
zero one two two .

From zend certification study guide.

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  1. Editorial Team
    Editorial Team
    2026-05-15T21:22:19+00:00Added an answer on May 15, 2026 at 9:22 pm

    Because on the second loop, $v is still a reference to the last array item, so it’s overwritten each time.

    You can see it like that:

    $a = array ('zero','one','two', 'three');
    
    foreach ($a as &$v) {
    
    }
    
    foreach ($a as $v) {
      echo $v.'-'.$a[3].PHP_EOL;
    }
    

    As you can see, the last array item takes the current loop value: ‘zero’, ‘one’, ‘two’, and then it’s just ‘two’… : )

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