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Home/ Questions/Q 8896039
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T23:56:28+00:00 2026-06-14T23:56:28+00:00

I have this code and no code before it that refers to any variables

  • 0

I have this code and no code before it that refers to any variables seen below. Yet I still can’t find why I’m getting the error: “First argument should be an array in…”

$array = array("element here for reason");

function sortdata()
{
    $File = fopen("Names.txt", "r");

    //put each file line into an array element
    while(!feof($File))
    {
        array_push($array, fgets($File));
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T23:56:29+00:00Added an answer on June 14, 2026 at 11:56 pm

    $array is out of scope to the function. You can bring it into scope using global.

    $array = ..;
    function sortdata() {
        global $array;
        ...
    }
    sortdata();
    

    Alternatively, you can pass it by reference into the function.

    $array = ..;
    function sortdata(&$array) {
        ...
    }
    sortdata($array);
    
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