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Home/ Questions/Q 4627332
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T03:33:10+00:00 2026-05-22T03:33:10+00:00

I have this code below and I’m getting the error upon compilation: error: cannot

  • 0

I have this code below and I’m getting the error upon compilation:

error: cannot convert 'const char*' to 'std::string*' for argument '1' to 'void sillyFunction(std::string*, int)'

#include <iostream>
#include <string>

using namespace std;
int counter = 0;

void sillyFunction(string * str, int cool=0);

int main(){
    sillyFunction("Cool");
    sillyFunction("Cooler", 1);
    return 0;
}

void sillyFunction(string * str, int cool){
    counter++;
    if (cool){
        for (int i=0; i<counter; i++) cout << *str << endl;
    } else {
        cout << *str << endl;
    }
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T03:33:11+00:00Added an answer on May 22, 2026 at 3:33 am

    Don’t take your parameter in as a string * try just using a const string & instead

    EDIT:

    std::string and const char* are different types. the std::string already has a conversion from string literals (ex: "Cool") to the actual string object. So by passing in the string literal "Cool" you are in a sense passing in a std::string object, not a pointer to one.

    The reason I chose to use a const string & is mostly from personal coding practices. This minimizes stack memory usage, and since you are passing in a constant string literal, there is no need for the parameter to be modify-able.

    Also don’t forget if you change from a string * that you no longer need to dereference it in your cout:

    if (cool){
        for (int i=0; i<counter; i++) cout << str << endl;
    } else {
        cout << str << endl;
    }
    
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