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Home/ Questions/Q 7159421
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:13:43+00:00 2026-05-28T13:13:43+00:00

I have this code below #include <stdio.h> int main(){ int i=0; for(i=0; i<1000; i++)

  • 0

I have this code below

#include <stdio.h>

int main(){

int i=0;
    for(i=0; i<1000; i++) {
    int count2 = 2;
    test_val(count2);
    sleep(1);
    printf("zzz..\n");
    }
    return 1;
}

int test_val(count)
{
  FILE *p;
  p = fopen("test.txt", "ab");
    if(p == NULL)
    {
      printf("Unable to open file!");
     return 0;
    }
 fprintf(p, "count is %d\n", count);

return 1;

}

I compiled this function with name “test”
Where with this function, it will print 2 until 1000 times. It will put everything in test.txt if this function is run correctly. But if I in the middle of iteration (let’s say I have already run 500 iterations)
I run kill-9 test (or ctrl+c), it will kill the program.

I thought at first I will get at least in test.txt 500 times “count is 2” printed there (until I send a kill signal), but in fact, it does not. It works if I wait until the program finishes and printing “count is 2 . What actually happen ?

I need to make a program that can cancel in the middle of iteration, and can still print until the latest iteration before kill execution in the text..

Thank you for any response

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:13:44+00:00Added an answer on May 28, 2026 at 1:13 pm

    stdio I/O functions are buffered, the C library keeps a buffer, and flushes it under certain circumstances. You can flush an output buffer explicitly using fflush(). fclose() does an implicit flush before closing a file.

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