Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6059635
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T08:44:01+00:00 2026-05-23T08:44:01+00:00

I have this code below. It works if i use only ONE WHERE variable

  • 0

I have this code below. It works if i use only ONE WHERE variable but the moment i add another one, the query doesn’t work.

It works if i just use this one all unions:

       where table_constant.user_id = '$uid'

But when i use this one below, it doesn’t work:

      where table_constant.user_id = '$uid' and table_one.something <> '$uid'

Code:

  $sql = "select table_one.field1, table_constant.field1, 
table_one.field2, table_one.field3, table_one.field4, 
table_one.field5, table_constant.c_id
from table_one LEFT JOIN table_constant on table_one.field1 
= table_constant.c_id 
where table_constant.user_id = '$uid' and table_one.something <> '$uid'
UNION
select table_two.field1, table_constant.field1, table_two.field2, 
table_two.field3,    table_two.field4, table_two.field5, table_constant.c_id
from table_two LEFT JOIN table_constant on table_two.c_id 
= table_constant.c_id 
where table_two.added_by = '$uid' and table_two.something <> '$uid'
UNION 
select table_three.field1, table_constant.field1, table_three.field2, 
table_three.field3, table_three.field4, table_three.field5,
table_constant.c_id
from table_three LEFT JOIN table_constant ON table_three.c_id 
= table_constant.c_id
where table_constant.user_id = '$uid' and table_three.something <> '$uid'
UNION
select table_four.field1, table_constant.field1, table_four.field2, 
table_four.field3, table_four.field4, table_four.field5, 
table_constant.c_id
from table_four LEFT JOIN table_constant ON table_four.c_id 
= table_constant.c_id
where table_constant.user_id = '$uid' and table_four.something <> '$uid'
ORDER BY date DESC LIMIT $start, $limit";
$result = mysql_query($sql);
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T08:44:02+00:00Added an answer on May 23, 2026 at 8:44 am

    On second thought I have a decent guess as to what the problem might be. When you write a LEFT JOIN, I presume you do so because there might be some rows that don’t match anything on the right side of the join. If you’d like to constrain those rows that do match in some way, you need to do so in the JOIN itself. For example:

    LEFT JOIN table_constant ON table_one.field1 = table_constant.c_id AND table_constant.user_id = '$uid'
    

    By placing the second condition in the WHERE clause, you’re essentially turning the left join into an inner join by forcing the right side to have a value.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have this code, which works fine, but I would like to be able
I have this code in jQuery, that I want to reimplement with the prototype
I have this code: chars = #some list try: indx = chars.index(chars) except ValueError:
I have this code that performs an ajax call and loads the results into
I have this code #include <iostream> using namespace std; int main(int argc,char **argv) {
I have this code: CCalcArchive::CCalcArchive() : m_calcMap() { } m_calcMap is defined as this:
I have this code: myVariable which I want to change into trace(myVariable: + myVariable);
I have this code while($row = mysql_fetch_row($result)) { echo '<tr>'; $pk = $row[0]['ARTICLE_NO']; foreach($row
I have this code <?php session_start(); if (isset($_GET[cmd])) $cmd = $_GET[cmd]; else die(You should
I have this code :- using (System.Security.Cryptography.SHA256 sha2 = new System.Security.Cryptography.SHA256Managed()) { .. }

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.