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Home/ Questions/Q 908119
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:39:58+00:00 2026-05-15T16:39:58+00:00

I have this code: clearTimeout(tooltiptimeout); tooltiptimeout=; $(#tool).fadeOut(slow).queue(function(){ tooltiptimeout=setTimeout(function(){ $(#tool).css(left,item.pageX-33); $(#tool).css( top,item.pageY-95); $(#tool).fadeIn(slow); }, 1000);

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I have this code:

clearTimeout(tooltiptimeout);
tooltiptimeout="";

$("#tool").fadeOut("slow").queue(function(){
    tooltiptimeout=setTimeout(function(){
        $("#tool").css("left",item.pageX-33);
        $("#tool").css( "top",item.pageY-95);
        $("#tool").fadeIn("slow");
    }, 1000);
    $(this).dequeue();
});

What it should do is this: As the user hovers his/her mouse over an object, a tooltip will show up there. Then when the user moves the mouse away, the tooltip should immediately start fading out. Later when the user rests his/her mouse on another object, a timeout of 1 second is called before the tooltip shows up at the new location.

The problem is, right now the fadeout does not get called immediately, and instead only occurs when the setTimeout occurs. (ie instead of first fading out then showing up a while later. Right now the tooltip stays in place, then a while later, it fades out and then fades in at new location).

What gives?

BTW, this code has the same problem:

    $("#tool").fadeOut("slow",function(){
    tooltiptimeout=setTimeout(function(){
        $("#tool").css("left",item.pageX-33);
        $("#tool").css( "top",item.pageY-95);
        $("#tool").fadeIn("slow");
    }, 1000);
});
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  1. Editorial Team
    Editorial Team
    2026-05-15T16:39:58+00:00Added an answer on May 15, 2026 at 4:39 pm

    Edit: Changed the answer based on updated comment below.

    Try the following:

    $("#tool").fadeOut("slow").delay('1000')
        .css("left",item.pageX-33)
        .css( "top",item.pageY-95)
        .fadeIn("slow");
    
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