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Home/ Questions/Q 7575135
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T16:36:40+00:00 2026-05-30T16:36:40+00:00

I have this code: $(‘#customerPaymentTable > tbody > tr’).eq(index).after(<tr><td colspan=’6′><center> + $(‘#customerRecordForm’).load(url) + </center></td></tr>);

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I have this code:

$('#customerPaymentTable > tbody > tr').eq(index).after("<tr><td colspan='6'><center>" + $('#customerRecordForm').load(url) +  "</center></td></tr>");

The problem is it returns this value object Object instead of the div element. The weird part is if I load the div independently, I mean if I don’t insert it in the table row it is working.

The working code is:

$('#customerRecordForm').load(url);

How am I gonna make it work? I really need that div form to be inserted. Please help. Thanks in advance.

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  1. Editorial Team
    Editorial Team
    2026-05-30T16:36:41+00:00Added an answer on May 30, 2026 at 4:36 pm

    The issue is because $('#customerRecordForm').load(url); will fill the #customerRecordForm element with the HTML from the url and then return the jQuery object, not the HTML as a string.

    You have two options. Firstly, you could change the logic to get the HTML you require from an AJAX call, and then insert that into the table cell., like this:

    $.ajax({
        url: url,
        dataType: "html",
        success: function(html){
            $('#customerPaymentTable > tbody > tr').eq(index).after("<tr><td colspan='6'><center>" +  html +  "</center></td></tr>");
        }
    });
    

    Alternatively, you could append the cell, and then call the load() on that new element, like this:

    var $row = $('#customerPaymentTable > tbody > tr').eq(index);
    $row.after('<tr><td colspan='6' class="foo"></td></tr>');
    $(".foo", $row).load(url);
    
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