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Home/ Questions/Q 7590553
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T20:25:48+00:00 2026-05-30T20:25:48+00:00

I have this code: $(document).ready(function() { var MidUpperArmCircumference = 0; var TricepsSkinfold = 0;

  • 0

I have this code:

$(document).ready(function() {

 var MidUpperArmCircumference = 0;
 var TricepsSkinfold = 0;

function checkMethod(method,parameters){
    $('#'+method+'_check').change(function() {
    if (this.checked == true) {
        $.each(parameters, function() {
            $('.'+this).css('color','blue');
            this++;    //HERE IS THE ERROR!
        });
    }
    });
}

var parametersMuscleArea = ['TricepsSkinfold', 'MidUpperArmCircumference'];
checkMethod('MidUpperArmMuscleArea',parametersMuscleArea);
});

How can I increase the variables TricepsSkinfold and MidUpperArmCircumference inside the $.each function?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T20:25:49+00:00Added an answer on May 30, 2026 at 8:25 pm

    this is the string, not the a reference to the local variable. You can’t increase your variable by increasing the string. Also, you’re trying to refer to a local variable by a name as given in a string. With local variables, this can only be done via eval, or by namespacing the variables.

    This will work:

    var ns = {
        MidUpperArmCircumference: 0,
        TricepsSkinfold: 0
    };
    
    function checkMethod(method,parameters){
        $('#'+method+'_check').change(function() {
            if (this.checked == true) {
                $.each(parameters, function() {
                    $('.'+this).css('color','blue');
                    ns[this]++;    // <-- Fixed.
                });
            }
        });
    }
    
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