Question

I have this code:

filename = tkFileDialog.askopenfilename(initialdir="lists/custom/", filetypes=(("Word list",
                                        "*.tldr"), ("All files", "*.*")))

If I had a file called “dog.tldr”, is there a way to get only the file name of it instead of having a directory in front of it? Right now filename outputs something like

/dir/blah/dog.tldr

But I only want the dog.tldr. Is there a way?

Thanks.

Answer 1

os.path.split:

In [83]: full_path = "/dir/blah/dog.tldr"

In [84]: os.path.split(full_path)
Out[84]: ('/dir/blah', 'dog.tldr')

In [85]: os.path.split(full_path)[1]
Out[85]: 'dog.tldr'