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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:44:08+00:00 2026-05-14T06:44:08+00:00

i have this code: [Flags] public enum MyUriType { ForParse, ForDownload, Unknown } and

  • 0

i have this code:

[Flags]
public enum MyUriType {
    ForParse,
    ForDownload,
    Unknown
}

and then:

MyUriType uriType = MyUriType.ForDownload;

but, I was wondering why this returns true:

if ((uriType & MyUriType.ForParse) == MyUriType.ForParse)

When it is not set in the second code group. Please advise.

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:44:08+00:00Added an answer on May 14, 2026 at 6:44 am

    By default, the first field for an enum type is given the ordinal value 0.

    So, if uriType does not contain the MyUriType.ForParse flag, then uriType & MyUriType.ForParse actually equals 0, which counterintuitively evaluates to true when you compare it to MyUriType.ForParse for equality (which is also 0).

    If you break it down to bitwise arithmetic then the expression you’re evaluating is:

    ({something} & 0) == 0
    

    …which will always evaluate to true, no matter what the “something” is.

    Normally, when you define a Flags enum, you should actually specify values for each field:

    [Flags]
    public enum MyUriTypes
    {
        None = 0,
        ForParse = 1,
        ForDownload = 2,
        ForSomethingElse = 4,
        ForAnotherThing = 8
    }
    

    Each value should be a power of 2 so that they don’t conflict (every multiple of 2 is a binary shift-left).

    It’s also customary to name it as a plural, so that people who use the enum know that it is a Flags enum and can/should hold multiple values.

    If you define your enum this way, your test code will now evaluate to false if uriType does not have the ForParse bit set.

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