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Home/ Questions/Q 4564244
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T18:28:25+00:00 2026-05-21T18:28:25+00:00

I have this code for a Dropdown menu: var timeout = 500; var closetimer

  • 0

I have this code for a Dropdown menu:

var timeout    = 500;
var closetimer = 0;
var ddmenuitem = 0;

function jsddm_open()
{  jsddm_canceltimer();
   jsddm_close();
   ddmenuitem = $(this).find('ul').css('visibility', 'visible');
}

function jsddm_close()
{  if(ddmenuitem) ddmenuitem.css('visibility', 'hidden');}

function jsddm_timer()
{  closetimer = window.setTimeout(jsddm_close, timeout);}

function jsddm_canceltimer()
{  if(closetimer)
   {  window.clearTimeout(closetimer);
      closetimer = null;}}

$(document).ready(function() {
   $('#mainnavigation > li').bind('mouseover', jsddm_open)
   $('#mainnavigation > li').bind('mouseout',  jsddm_timer)});

document.onclick = jsddm_close;

and I want to modify it so the drop down will open on “Click”, not on “Mouseover” and to close on “Mouseout”. I’ve tried to use this:

$('#mainnavigation > li').bind('click', jsddm_open)

but it’s not working.

Someone can help me?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T18:28:25+00:00Added an answer on May 21, 2026 at 6:28 pm

    First, some HTML would help.

    Apart from that, I think your function works but clicking the <li> also triggers document.onclick = jsddm_close;
    So your menu opens and closes right away.

    Try to get rid of the document.onclick line and see if it works better

    You also need a return false; at the end of your jsddm_open() function

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