Question

I have this code for listing mysql records and putting it into a table according to the address inputted. My problem is, how to do just the same but this time, making use of textboxes to project the contents of the record corresponding to the same data inputted.
I’m just a beginner with no talent. Maybe you could give me some idea on how to do it.

       mysql_select_db("hospital", $con);

        $result = mysql_query("SELECT * FROM t2 WHERE ADDRESS='{$_POST["address"]}'");
         echo "<table border='1'>
     <tr>
     <th>HospNum</th>
     <th>RoomNum</th>
     <th>LastName</th>
     <th>FirstName</th>
    <th>MidName</th>
    <th>Address</th>
      <th>TelNum</th>
      <th>Nurse</th>
      </tr>";

      while($row = mysql_fetch_array($result))
   {
  echo "<tr>";
     echo "<td>" . $row['HOSPNUM'] . "</td>";
  echo "<td>" . $row['ROOMNUM'] . "</td>";
   echo "<td>" . $row['LASTNAME'] . "</td>";
   echo "<td>" . $row['FIRSTNAME'] . "</td>";
    echo "<td>" . $row['MIDNAME'] . "</td>";
      echo "<td>" . $row['ADDRESS'] . "</td>";
       echo "<td>" . $row['TELNUM'] . "</td>";
        echo "<td>" . $row['NURSE'] . "</td>";

  echo "</tr>";
     }
    echo "</table>";

 mysql_close($con);
   ?>

Answer 1

As a suggestion, I do not think displaying the values inside of a textbox is the best idea. With that being said, you achieve your results by performing the following

while($row = mysql_fetch_array($result)) {
 echo "<input type=\"text\" value='" . $row['HOSPNUM'] . "'><br />";
 echo "<input type=\"text\" value='" . $row['ROOMNUM'] . "'><br />";
 ....
}

You would need to escape the " inside of the text boxes by using PHP’s escape special character \