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Editorial Team
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Asked: 2026-05-25T20:10:33+00:00

I have this code function verifyKey(e) { var keycode; if (window.event) keycode = window.event.keyCode;

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I have this code 

function verifyKey(e)
{
    var keycode;
    if (window.event)
        keycode = window.event.keyCode;
    else if (e)
        keycode = e.which;
    regex=/[1-9]/;
    if(regex.test(keycode))
        return true;
    else
        void(0);
}

in the html I added an input and I add the onkeydown event onkeydown=”verifyKey(event);”

I like to verify the key before it display on the text

If the key is a number or coma(,) or full stop(.)
then accept the key
else
refuse it

Thanks

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1 Answer

  1. Editorial Team

    Here in your code you are testing the regular expression defined with the keycode, so every chearactes on the keyboard will be allowed since the keycode of every key is numbers, so you will not get the result what you expect. Instead of using the regular expression try the below code

    <html>
<head>
<script type="text/javascript">
function verifyKey(e)
{
    var keycode;
    if (window.event)
        keycode = window.event.keyCode;
    else if (e)
        keycode = e.which;


    if((keycode>=48 && keycode<=57))
    {alert("if")
        return true;
    }
    else if((keycode == 188)||(keycode == 190))
    {alert("elseif");
        return true;
    }
    else
    {alert("else")
        return false;
    }
}


</script>
</head>
<body>
<input type="text" onkeypress="return verifyKey(event)" />
</body>
</html>
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