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Home/ Questions/Q 7661179
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:33:50+00:00 2026-05-31T13:33:50+00:00

I have this code here: var fields = row.split(/regex goes here/); I want to

  • 0

I have this code here:

var fields = row.split(/regex goes here/);

I want to split row on each occurrence of

|

but not

*|

How do I write this simple regular expression. I thought there was a not character of sorts but I can’t seem to find a good reference right now.

I know I need to escape the special character | like this \|..but how do I add the not part?

Likely I will just switch my markup to

|*

instead of

*|

and than I can this form I found on MDN – match x only if not followed by y.

x(?!y)

I’m testing here:

http://www.regexpal.com/

Found a good reference here

http://www.regular-expressions.info/reference.html

https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp#Special_characters_in_regular_expressions

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:33:50+00:00Added an answer on May 31, 2026 at 1:33 pm

    Don’t split() on the delimiter. Just .match() everything between delimiters:

    var fields = row.match(/(?:\*\||[^|])*/g);
    

    Explanation:

    (?:    # Match either
     \*\|  # *|
    |      # or
     [^|]  # any character except |
    )*     # Repeat as needed
    
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