Question

I have this code:

if "%2"=="32" (
set bit=This is 32bit
)
if "%2"=="64" (
set bit=This is 64bit
)
echo %bit%
)

When I tried using sample.bat /s 64 the output is “This is 64bit”, but when I tried using sample.bat /s 32 the output is still “This is 64bit”. Then I switch it back to sample.bat 64 the ouput became “This is 32bit”. I think the variable initialization is being delayed. Does someone know a workaround?

Answer 1

If you run sample.bat 64, the 64 is in %1, not %2. The first parameter passed to the batch file is always %1 – the name of the batch file itself is in %0. You’re getting some random output remnant or something left over from another attempt. Try this:

setlocal
if "%1"=="32" (
set bit=This is 32bit
)
if "%1"=="64" (
set bit=This is 64bit
)
echo %bit%
)
endlocal

setlocal makes sure that any environmental changes are discarded when your batch file ends, so you don’t have to worry about getting leftovers from testing.

This still won’t work properly if you just type sample.bat, because you haven’t dealt with no parameters at all being passed.