Question

I have this code

if (hashtable_count(h) > 0)
    {
      do {
          kk = (key*)hashtable_iterator_key(itr);
          v =(value*) hashtable_iterator_value(itr);
....

key and value are both declared in the same code block as

 struct key *k, *kk;
struct value *v;

and VC 2010 reports the following error

error C2065: ‘key’ : undeclared identifier

error C2059: syntax error : ‘)’

error C2065: ‘value’ : undeclared identifier

error C2059: syntax error : ‘)’

the errors are for the two assignment lines. Two first errors are for the first assignment statement and the next for the last one.

I will be happy to give more details if neccessary.

More information:
Here are the two functions

 void * hashtable_iterator_key(struct hashtable_itr *i)
  { return i->e->k; }

void * hashtable_iterator_value(struct hashtable_itr *i)
  { return i->e->v; }

If I don’t type cast the returned value to key*, it reports type mismatch error

Answer 1

(key*) in you cast should be (struct key*)

You have not created the the type “key”.

i.e. you have not done:

typedef struct
{
   <some defines>
} key;

Then (key*) would work.