Question

I have this code:

import thread

def print_out(m1, m2):
    print m1
    print m2
    print "\n"

for num in range(0, 10):
    thread.start_new_thread(print_out, ('a', 'b'))

I want to create 10 threads, each thread runs the function print_out, but I failed. The errors are as follows:

Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr
Unhandled exception in thread started by 
sys.excepthook is missing
lost sys.stderr

Answer 1

First of all, you should use the higher level threading module and specifically the Thread class. The thread module is not what you need.

As you extend this code, you most likely will also want to wait for the threads to finish. Following is a demonstration of how to use the join method to achieve that:

import threading

class print_out(threading.Thread):

    def __init__ (self, m1, m2):
        threading.Thread.__init__(self)
        self.m1 = m1
        self.m2 = m2

    def run(self):
        print self.m1
        print self.m2
        print "\n"

threads = []
for num in range(0, 10):
    thread = print_out('a', 'b')
    thread.start()
    threads.append(thread)

for thread in threads:
    thread.join()