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Home/ Questions/Q 6156943
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T20:42:00+00:00 2026-05-23T20:42:00+00:00

I have this code in a function, but when it runs it does a

  • 0

I have this code in a function, but when it runs it does a long pause and then it says:

$floating point exception

I am assuming this is due to multiple conditions in the for loop, but I don’t know why it is wrong. Any ideas?

int i,j,number=5;
for (i = 2; (i < number || j==1); i++)
{
    if (number%i==0)
    {
        j = 1;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-23T20:42:02+00:00Added an answer on May 23, 2026 at 8:42 pm

    floating point exception – This means there’s an arithmetic error.

    It looks like you’re trying to stop the loop with j, but what you’re actually doing is continuing the loop forever (because once you get j==1 the or condition is always true).
    What then happens is you loop i through all the Integer values back to 0 and get the exception.

    What I think you want to do is :

    for (i = 2; (i < number); i++)
    {
        if (number%i==0)
        {
            j = 1;
            break;
        }
    }
    
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