Question

I have this code in a prepareForSegue method

    // Get destination view
    UIViewController *viewController = [segue destinationViewController];

    //See if it responds to a selector
    if ([viewController respondsToSelector:@selector(setSomethingOrOther:)]) {
        //if so call it with some data
        [viewController setSomethingOrOther:something];
    }

The code above means I do not have to include a reference to the actual class of the view controller being segue’d to. I can more loosely couple the two view controllers and just check if it responds to some property being set on it.

The problem is that when I do this I get the following compile time error:

No visible @interface for ‘UIViewController’ declares the selector ‘setSomethingOrOther:’

which is true of course. I know I could get around it by including a reference to the view but I would prefer to keep it separated. How can I work around this

Answer 1

Use the performSelector:aSelector method, then you can call an undeclared selector.