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Home/ Questions/Q 7763565
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T14:41:28+00:00 2026-06-01T14:41:28+00:00

I have this code in C (it’s for study only): char x; uint64_t total

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I have this code in C (it’s for study only):

    char x;
    uint64_t total = 0;

    for(x = 20; x < 30; x++){
        total = (((((1 << x) * x) / 64) + 1) * sizeof(uint64_t));
        printf("%d - %llu\n", x, total);        
    }       

What is printed:

20 - 2621448
21 - 5505032
22 - 11534344
23 - 24117256
24 - 50331656
25 - 104857608
26 - 218103816
27 - 18446744073625665544
28 - 18446744073575333896
29 - 18446744073508225032

Why at x > 26 do I have those strange values? I’m at gcc 4.6.1 on Ubuntu 10.10 64 bits.

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  1. Editorial Team
    Editorial Team
    2026-06-01T14:41:29+00:00Added an answer on June 1, 2026 at 2:41 pm

    Because 1 is an int, 32 bits, so (1 << 27)*27 overflows. Use 1ull.

    Regarding your comment, if x is a uint64_t, then 1 << x is still an int, but for the multiplication it would be cast to uint64_t, so there’d be no overflow. However, if x >= 31, 1 << x would be undefined behaviour (as the resulting value cannot be represented by a signed 32 bit integer type).

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