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Home/ Questions/Q 3442074
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Editorial Team
  • 0
Editorial Team
Asked: May 18, 20262026-05-18T08:37:38+00:00 2026-05-18T08:37:38+00:00

I have this code in PHP $max=SELECT MAX(num) FROM info; $maxquery= mysql_query($max) or die

  • 0

I have this code in PHP

$max="SELECT MAX(num) FROM info";
$maxquery= mysql_query($max) or die (died);
while($row = mysql_fetch_array($maxquery)){
    echo "The max num is ". $row['num']."this is it";
}
$maxnum= mysql_fetch_array($maxquery);
echo "<br>".$maxnum."hh";

then the output be:

The max num is this is it

hh


Why didn’t the query get the max number?

The table is called info and it has these fields, ID, num, title, description, and answer.


After editing:

I tried my query in MySQL and it works fine!

“SELECT MAX(num) FROM info”

and this is my complete code if it can help:

<?php
    $answer=$_GET["answerbox"];
    $ID=$_GET["TheID"];

    $host="localhost";
    $username="root";
    $password="";
    $db_name="game";
    mysql_connect("$host","$username","$password")or die("cannot connect");
    mysql_select_db("$db_name")or die("cannot select DB");

    $max="SELECT MAX(num) FROM info";
    $maxquery= mysql_query($max) or die (died);
    while($row = mysql_fetch_array($maxquery)) {
        echo "The max num is ". $row['num']."this is it";
    }

    $maxnum= mysql_fetch_array($maxquery);
    $sql="SELECT * FROM info  WHERE ID=".$ID;
    $query = mysql_query($sql) or die(errorquery);
    $row = mysql_fetch_array($query);
    $trueanswer = $row['Answer'];
    $num=$row['num'];
    if ($num<$maxnum)
    {
        $numto= $num +1 ;
        echo "<br>".$maxnum."hh";
    }
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T08:37:39+00:00Added an answer on May 18, 2026 at 8:37 am

    Then the code will be

    $max="SELECT MAX(num) as num FROM info";
    $maxquery= mysql_query($max) or die (died);
    while($row = mysql_fetch_assoc($maxquery)) {
        echo "The max num is ". $row['num']."this is it";
    }
    
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