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Home/ Questions/Q 517195
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:48:33+00:00 2026-05-13T07:48:33+00:00

I have this code: inp = int(input("Enter a number:")) for i in inp: n

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I have this code:

inp = int(input("Enter a number:"))

for i in inp:
    n = n + i;
    print (n)

but it throws an error: 'int' object is not iterable

I wanted to find out the total by adding each digit, for eg, 110. 1 + 1 + 0 = 2. How do I do that?

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:48:33+00:00Added an answer on May 13, 2026 at 7:48 am

    First, lose that call to int – you’re converting a string of characters to an integer, which isn’t what you want (you want to treat each character as its own number). Change:

    inp = int(input("Enter a number:"))
    

    to:

    inp = input("Enter a number:")
    

    Now that inp is a string of digits, you can loop over it, digit by digit.

    Next, assign some initial value to n — as you code stands right now, you’ll get a NameError since you never initialize it. Presumably you want n = 0 before the for loop.

    Next, consider the difference between a character and an integer again. You now have:

    n = n + i;
    

    which, besides the unnecessary semicolon (Python is an indentation-based syntax), is trying to sum the character i to the integer n — that won’t work! So, this becomes

    n = n + int(i)
    

    to turn character '7' into integer 7, and so forth.

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