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Home/ Questions/Q 563825
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:42:03+00:00 2026-05-13T12:42:03+00:00

i have this code: $(.link).each(function() { group += 1; text += 1; var links

  • 0

i have this code:

    $(".link").each(function() {
            group += 1;
            text += 1;
            var links = [];
            links[group] = [];

            links[group][text] = $(this).val();
        }
    });

    var jsonLinks = $.toJSON(links);

after it has looped every .link it will exit the each loop and encode the array ‘links’ to json. but the array ‘links’ is a local variable inside the each-loop. how can i make it global outside the loop?

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:42:04+00:00Added an answer on May 13, 2026 at 12:42 pm

    Define links outside the loop:

    var links = [];
    $(".link").each(function() {
      group += 1;
      text += 1;
      links[group] = [];
      links[group][text] = $(this).val();
    });
    var jsonLinks = $.toJSON(links);
    

    I should also point out that this doesn’t make a lot of sense because you will end up element 7, for example, being an array with a single element (indexed as 7) to the value. Is this really what you want?

    What I imagine you want is an array of the values. If so, why not use map()?

    var links = $(".link").map(function(i, val) {
      return $(val).val();
    });
    
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