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Home/ Questions/Q 7561305
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T13:07:48+00:00 2026-05-30T13:07:48+00:00

I have this code: namespace Some\Different\Name; try { $reflect = new ReflectionClass($class); X: $instance

  • 0

I have this code:

namespace Some\Different\Name;
        try {
            $reflect  = new ReflectionClass($class);
X:          $instance = $reflect->newInstanceArgs($args);
        } catch (ReflectionException $e) {
            exit($e->getMessage());
        }

and I’m testing it trying to make a ReflectionException be thrown. And it gives me:

Fatal error: Uncaught exception ‘ReflectionException’ with message
‘Class MyClass does not have a constructor, so you cannot pass any
constructor arguments’ in … on line X.

What am I doing wrong?

PS: I know why the exception is thrown, I just wanna know why it’s not caught!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T13:07:50+00:00Added an answer on May 30, 2026 at 1:07 pm

    Finally. It was a namespace problem. It’s strange by the way that PHP doesn’t notify that you are trying to catch an exception of a type (ReflectionException) that doesn’t exists in the current namespace.

    Just adding the \ to \ReflectionException helped me out because now it’s able to find what type of exception I’m actually looking for.

    Another solution would be to add:

    use \ReflectionException;
    

    just after the namespace declaration.

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