Question

I have this code:

Node main_node = document.getDocumentElement();
NodeList main_node_list = main_node.getChildNodes();
for( int main_iterator = 0; main_iterator < main_node_list.getLength(); main_iterator++ ) {
    Node child_node = main_node_list.item( main_iterator );
    String child_node_name = child_node.getNodeName();
    if( child_node_name == "#text" ) continue;
    Toast.makeText( context, "\"" + child_node_name + "\"", Toast.LENGTH_SHORT ).show();
    if( child_node_name == "library_visual_scenes" ) {
    ...
    }
}

It can’t be any clearer, but in the Toast between the two if statements, it shows that child_node_name is exactly equal “library_visual_scenes” at some point. This without the second if statement being true.

The first if statement, when child_node_name is equal “#text” does get executed. Meaning I never see the text “#text” in the Toast.

child_node_name is a String object. Is this the correct way to compare a String with a character string?

I cannot find out what’s going on here. Could this be some Android specific thing, as nearly the same code works if I run it as plain Java on my computer?

Answer 1

Replace

child_node_name == "library_visual_scenes"
child_node_name == "#text"

With

"library_visual_scenes".equals(child_node_name);
"#text".equals(child_node_name);

That is how you must compare Strings in java. “==” compares references, not contents.