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Home/ Questions/Q 9000493
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T00:19:05+00:00 2026-06-16T00:19:05+00:00

I have this code <?php $files = array(‘includes/s.xlsx’, ‘includes/test.html’); $zipname = ‘file.zip’; $zip =

  • 0

I have this code

<?php
$files = array('includes/s.xlsx', 'includes/test.html');
$zipname = 'file.zip';
$zip = new ZipArchive;
$zip->open($zipname, ZipArchive::CREATE);
foreach ($files as $file) {
  $zip->addFile($file);
 }
$zip->close();


header('Content-Type: application/zip');
header('Content-disposition: attachment; filename=filename.zip');
header('Content-Length: ' . filesize($zipname));
readfile($zipname);

But i don’t want to make the zip file saved to the server i just want it to be served to the users.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T00:19:06+00:00Added an answer on June 16, 2026 at 12:19 am

    ZIP is not a streamable format (the target needs to support seeking, i.e. a ZIP file cannot be simply written to a target where the previously-written data cannot be re-read and modified) what you are trying to do can’t work. So the best solution (if your zip files won’t be huge) is creating it in a temporary location, readfile() it and then delete the temporary file.

    See the following Stack Overflow questions for further reference. They contain some workarounds that might be fine for you:

    • Zip Stream in PHP
    • LAMP: How to create .Zip of large files for the user on the fly, without disk/CPU thrashing
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