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Home/ Questions/Q 8411587
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T00:27:29+00:00 2026-06-10T00:27:29+00:00

i have this code: private Bitmap disk1, disk2, disk3; private ArrayList<Bitmap> bitmapArray = new

  • 0

i have this code:

private Bitmap disk1, disk2, disk3;
private ArrayList<Bitmap> bitmapArray = new ArrayList<Bitmap>();
......
disk1 = BitmapFactory.decodeResource(getResources(), R.drawable.disk01);
disk1 = Bitmap.createBitmap(disk1, 0, 0, origW, origH, matrix, true);
disk2 = BitmapFactory.decodeResource(getResources(), R.drawable.disk02);
disk2 = Bitmap.createBitmap(disk2, 0, 0, origW, origH, matrix, true);
disk3 = BitmapFactory.decodeResource(getResources(), R.drawable.disk03);
disk3 = Bitmap.createBitmap(disk3, 0, 0, origW, origH, matrix, true);

bitmapArray.add(disk1);
bitmapArray.add(disk2);
bitmapArray.add(disk3);

i think to optimise code i can use this construction without bitmaps (with for loop):

 bitmapArray.add(Bitmap.createBitmap(BitmapFactory.decodeResource(getResources(),
                        R.drawable.disk01), 0, 0, origW, origH, matrix, true));

but i’m little confused: it will store the result of methods or it will be call those methods every time when i try to get bitmapArray.get(0)?

thanx


update: i will use array after in handler callback to change animation on canvas:

Bitmap item;
.......
public Handler.Callback hc = new Handler.Callback() {
        public boolean handleMessage(Message msg) {
                    switch (msg.what) {
                    case 1:
                        if (ai == 8)
                            ai = 0;
                        item = bitmapArray.get(ai);
                        ++ai;
                        break;

maybe it is not call “optimization”, and I had to say “readability”

sorry for my bad english

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T00:27:30+00:00Added an answer on June 10, 2026 at 12:27 am

    get() just looks at a given position and returns whats there.
    add() just adds what was passed to it.

    There is no difference in

    disk1 = BitmapFactory.decodeResource(getResources(), R.drawable.disk01);
    disk1 = Bitmap.createBitmap(disk1, 0, 0, origW, origH, matrix, true);
    bitmapArray.add(disk1);
    

    or

    bitmapArray.add(Bitmap.createBitmap(BitmapFactory.decodeResource(getResources(),
                            R.drawable.disk01), 0, 0, origW, origH, matrix, true));
    

    since the result of

    Bitmap.createBitmap(BitmapFactory.decodeResource(getResources(),
                                R.drawable.disk01), 0, 0, origW, origH, matrix, true));
    

    is a Bitmap, regardles of saving it to an Bitmap object first or not.
    It is like drinking from a bottle, you can fill it in a glas first, or drink directly from the bottle, in both cases you enjoy Cola or whatever.

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