Question

I have this code:

<script>
    $(function() {
        $("#tabs").tabs({ event: "mouseover" });        
        $("#tabs").tabs("add","#tab-4","Friends Discussions");
        $("#tabs").tabs("add","#tab-5","Announcements");
        $("#tabs").tabs("add","#tab-6","Contact");
    });
</script>

<div class="demo" align="center" >
    <div id="tabs">
        <ul>
            <li><a href="#tabs-1">Recent Discussions</a></li>
            <li><a href="#tabs-2">Most Popular Discussions</a></li>
            <li><a href="#tabs-3">Most Viewed Discussions</a></li>
        </ul>

        <div id="tabs-1">
            <p>111111111111</p>
        </div>

        <div id="tabs-2">
            <p>222222222222</p>
        </div>

        <div id="tabs-3">
            <p>333333333333333</p>
        </div>

        <div id="tabs-4">
            <p>4444444444</p>
        </div>

        <div id="tabs-5">
            <p>555555555</p>
        </div>

        <div id="tabs-6">
            666666666
        </div>
    </div>
</div>

Tabs 4, 5 and 6 have got the same content as appears in tab 1, 2 and 3. Why does that happen?

Answer 1

You made a typo in the tabs you’re adding. The id of the divs has to match the second parameter of each function.

Your divs look like this:

<div id="tabs-4">

But your code references:

$("#tabs").tabs("add","#tab-4","Friends Discussions");
                           ^
                           s is missing

Try this code instead:

http://jsfiddle.net/ugjLs/

$(function() {
    $( "#tabs" ).tabs({
        event: "mouseover"
    });

    $( "#tabs" ).tabs("add","#tabs-4","Friends Discussions");
    $( "#tabs" ).tabs("add","#tabs-5","Announcements");
    $( "#tabs" ).tabs("add","#tabs-6","Contact");
});