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Home/ Questions/Q 5943395
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T16:23:21+00:00 2026-05-22T16:23:21+00:00

I have this code: secondArray = [firstArray objectAtIndex:1]; The object at index 1 is

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I have this code:

secondArray = [firstArray objectAtIndex:1];

The object at index 1 is already an NSMutableArray inside [firstArray]. The problem is that when I change secondArray, the firstArray also changes.

How can I stop this?

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  1. Editorial Team
    Editorial Team
    2026-05-22T16:23:22+00:00Added an answer on May 22, 2026 at 4:23 pm

    The best way to keep it from changing is to copy the array instead of set it. I had that problem before, and this is what did the trick for me

    EDIT: just so I don’t give you poor information, I’m going to change this to a more generalized version:

    NSMutableArray *secondArray = [NSMutableArray alloc] initWithCapacity:[[firstArray objectAtIndex:1] count];
    [secondArray addObjectsFromArray:[firstArray objectAtIndex:1]];
    

    This should better fit your situation. I have tested it twice to be sure by creating arrays and cloning them, then modifying the clones to see they are the only objects being modified

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