Question

i have this code that will check the array contains the specific string and outputs the data needed, but it is inside a function thus the output was done using a concatenate “.=”, i did try the in_array function in its basic form
i.e

$show = array();
$show[] = "dog";
$show[] = "doga";
$show[] = "dogasd";
$show[] = "cat asd";
print_r($show);
if(in_array("cat asd", $show))
{
echo "found";
}
else
{
echo "not found";
}

and it is working, but in here:

public function personal(){

            $sql_field = "SELECT * FROM somewhere WHERE show_field = 1";
    $result = mysql_query($sql_field);
    $num = mysql_num_rows($result);

    $show = array();
    for($i=0;$i<$num;$i++)
    {
        $row = mysql_fetch_assoc($result);
        $show[] = $row['field_name']."<br>";
    }

            $block .= "<tr>";
    $block .= $show[0];

        if(in_array("firstName", $show))
        {
            $block .= "<td style=\"width: 250px;\"><div class=\"fields\"><input type=\"text\" title=\"First Name*\" value=\"{$this->detail("firstName")}\" name=\"first_name\" class=\"placeholder textbox-long\" /></div></td>";
        }
        if(in_array("lastName", $show))
        {
            $block .= "<td style=\"width: 250px;\"><div class=\"fields\"><input type=\"text\" title=\"Last Name*\" value=\"{$this->detail("lastName")}\" name=\"last_name\" class=\"placeholder textbox-long\" /></div></td>";
        }
    $block .= "</tr>";

    }

it always outputs false thus not displaying anything, i tried this with a non array variable and its working fine, so my guess is that array does not work great inside a function? correct me if i’m wrong here. And i need the array for this functionality to work
any ideas guys?

Thank You 🙂

Answer 1

in_array() works just fine inside of functions, however you’re expecting it to search for a substring, which it does not do. If you were to search for firstName<br> it would find what you’re looking for since you added firstName<br> to the array, but firstName is not in the array.