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Home/ Questions/Q 7754099
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T12:13:22+00:00 2026-06-01T12:13:22+00:00

I have this code to create a webapp in my server: import web urls

  • 0

I have this code to create a webapp in my server:

import web

urls = (
    '/update', 'Update',
)

app = web.application(urls, globals())


class Update:

    print "hola"

if __name__=='__main__':
    app.run()

When I try to execute:

python@ubuntu:~$ python prueba.py 8081
hola
http://0.0.0.0:8081/
Traceback (most recent call last):
  File "prueba.py", line 21, in <module>
    app.run()
  File "/usr/local/lib/python2.6/dist-packages/web/application.py", line 311, in run
    return wsgi.runwsgi(self.wsgifunc(*middleware))
  File "/usr/local/lib/python2.6/dist-packages/web/wsgi.py", line 54, in runwsgi
    return httpserver.runsimple(func, validip(listget(sys.argv, 1, '')))
  File "/usr/local/lib/python2.6/dist-packages/web/httpserver.py", line 148, in runsimple
    server.start()
  File "/usr/local/lib/python2.6/dist-packages/web/wsgiserver/__init__.py", line 1753, in start
    raise socket.error(msg)
socket.error: No socket could be created

Why is it happening?

Thank you in advance

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T12:13:24+00:00Added an answer on June 1, 2026 at 12:13 pm

    The error message says that it couldn’t create a listening socket on the specified port. Check if there is already a server running on port 8081.

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