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Home/ Questions/Q 8588061
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T22:43:20+00:00 2026-06-11T22:43:20+00:00

i have this code to show the info window in google maps var infoWindow

  • 0

i have this code to show the info window in google maps

 var infoWindow = new google.maps.InfoWindow({
    position: latlng,
    content: 'Hello, world'
  });

and i have a php code to retrieve the address from the database.

<?php
mysql_connect("localhost", "root", "root") or die (mysql_error ());
mysql_select_db("theaterdb") or die(mysql_error());
$strSQL =("SELECT address FROM theaters WHERE theater_name='" . mysql_real_escape_string($_POST['course']) . "'");
$rs = mysql_query($strSQL);
while($row = mysql_fetch_array($rs)) {
echo "<b>Theater Address:</b><br>";
echo $row['address'] . "<br /><br />";
 }
 mysql_close();
?>

Now i need to get the address from database to infowindow’s content field..how to do this? can anyone help me….thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-11T22:43:21+00:00Added an answer on June 11, 2026 at 10:43 pm

    Use mysql_fetch_assoc() and assign $row database values:

    <?php
        $link = mysql_connect("localhost", "root", "root") or die (mysql_error());
        mysql_select_db("theaterdb", $link) or die(mysql_error());
        $strSQL = "SELECT address FROM theaters WHERE theater_name='" . mysql_real_escape_string($_POST['course']) . "'";
        $rs = mysql_query($strSQL);
        $row = mysql_fetch_assoc($rs);
        mysql_close();
    ?>
    
    <script>
      var infoWindow = new google.maps.InfoWindow({
        position: latlng,
        content: '<b>Theater Address:</b><br> <?php echo $row['address']; ?>'
      });
    </script>
    

    For a side note, you can try to move your code to PDO as mysql_* functions are deprecated, check this nice tutorial.

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