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Home/ Questions/Q 3399124
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T04:43:58+00:00 2026-05-18T04:43:58+00:00

I have this code: var data_string = $(‘form#frm’).serialize(); $.ajax({ type: POST, url: /send.php, data:

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I have this code:

var data_string = $('form#frm').serialize();
    $.ajax({
        type:       "POST",
        url:        "/send.php",
        data:       data_string,
        success:    function(data) {
        alert(data);

And in the php file:

$to = mysql_real_escape_string($_POST['email']);    //email
$name = mysql_real_escape_string($_POST['name']);   //name of tipper
$msg = mysql_real_escape_string($_POST['msg']);     //message
echo $name; //EXAMPLE

The above alert in the ajax code SHOULD alert the posted $name variable.
However, the alertbox comes up, but it is blank.

I think it has to do with the serialize part.

echoing 1 or 0 from php works fine, and the alert box shows the 1 or 0.

Any ideas whats wrong?

Thanks

EDIT:

Found out that when alerting the serialized data:

 alert (data_string);

I get “undefined”…

And here is the form:

<form name='frm' id='frm' action='send.php' method='post' onsubmit='tip_func(); return false;'>

<input type='text' name='name' id='name'>

tip_func() is the function where all the above ajax is…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T04:43:59+00:00Added an answer on May 18, 2026 at 4:43 am

    Have you tested the data_string? Try doing an alert on it first to check it has data in it!

    var data_string = $('#frm').serialize();
    alert(data_string);
    
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