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Home/ Questions/Q 7963607
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T05:38:47+00:00 2026-06-04T05:38:47+00:00

I have this code: void changeToCapital(char* str) { int i; for (i=0; i<strlen(str); i++)

  • 0

I have this code:

void changeToCapital(char* str)
{
    int i;
    for (i=0; i<strlen(str); i++) 
    {
        str[i] =str[i] -32;
    }
}

and this method is supposed to get a char* variable, and change it to its uppercase. For some reason I’m getting an error saying EXECUTE_BAD_ACCESS.

The calling function:

char* s = "itzik";
changeToCapital(s);
printf("%s\n",s);

What am I doing wrong here?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T05:38:48+00:00Added an answer on June 4, 2026 at 5:38 am

    This is most likely because you are passing it a pointer to non-writable memory, such as one obtained from a string literal:

    char *ptr = "Hello";
    changeToCapital(ptr); // <<== ERROR !
    

    You can change the call to avoid the error:

    char ptr[] = "Hello";
    changeToCapital(ptr);
    

    On a side note, your change to upper case works only when all letters are in the lower case. You should use toupper(ch) function instead of subtracting 32.

    void changeToCapital(char* str) {
        for (; *str = toupper(*str) ; str++)
            ;
    }
    
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