Question

i have this code which is not seeming to work, what i want to do is make a query to understand users’ level, and then based on that level i need to print different content, for the moment it prints the default one, and i get this error message:

mysql_result() expects parameter 1 to be resource, boolean given on this line:

$rank = mysql_result($rank1, 0, 'rank');

the code is like this:

session_start();
if(!$_SESSION['username']){

header("location:login.php"); // Redirect to login.php page
}
else //Continue to current page
header( 'Content-Type: text/html; charset=utf-8' );
$rank1 = mysql_query("SELET access FROM tbl_galleries WHERE column='username" . mysql_real_escape_string($_SESSION['username']) . "'");
$rank = mysql_result($rank1, 0, 'rank');

switch ($rank)
{
case 3:
  echo "<div><a href='#'>Order DIAMOND Membership</a></div>";
  break;

case 2:
  echo "<div><a href='#'>Order PLATINUM Membership</a></div>
    <div><a href='#'>Order DIAMOND Membership</a></div>";
  break;

case 1:
  echo "<div><a href='#'>Order ELITE Membership</a></div>
    <div><a href='#'>Order PLATINUM Membership</a></div>
    <div><a href='#'>Order DIAMOND Membership</a></div>";
  break;

default:
  echo "<div><a href='#'>Order PRO Membership</a></div>
    <div><a href='#'>Order ELITE Membership</a></div>
    <div><a href='#'>Order PLATINUM Membership</a></div>
    <div><a href='#'>Order DIAMOND Membership</a></div>";
}

Answer 1

For SELECT, SHOW, DESCRIBE, EXPLAIN and other statements returning
resultset, mysql_query() returns a resource on success, or FALSE on
error.

For other type of SQL statements, INSERT, UPDATE, DELETE, DROP, etc,
mysql_query() returns TRUE on success or FALSE on error.

This means you have some error in your query. Try to finalize the query in phpMyAdmin or some other such tool. Your query should go something like this

$userName = mysql_real_escape_string($_SESSION['username']);
$sql = "SELECT access 
        FROM tbl_galleries 
        WHERE username = $userName";
$result = mysql_query($sql);
$rank = mysql_result($result, 0, 'access');