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Home/ Questions/Q 6973583
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T17:07:37+00:00 2026-05-27T17:07:37+00:00

I have this code which orders the numbers starting from the biggest one but

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I have this code which orders the numbers starting from the biggest one but its kinda confusing for me:

    #include <iostream>
using namespace std;

int main()
{
 const int n=5;
 int i, j, t, a[n]={15,9,8,7,5};

 cout << "a[]={";
 for(i=0; i<n; i++) cout << a[i] << " ";
 cout << "} \n\n";

 for(i=0; i<n-1; i++)
   for(j=i+1; j<n; j++)
     if(a[i]>a[j]){
       t=a[i];
       a[i]=a[j];
       a[j]=t;
     }

 cout << "Pas radhitjes inkrementuese \n\n"
      << "a[]={";
 for(i=0; i<n; i++) cout << a[i] << " ";
 cout << "} \n\n";


 cin.get();cin.get();
return 0;
}

Is there any other way to order numbers from 1 array, starting from the biggest/lowest number?

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  1. Editorial Team
    Editorial Team
    2026-05-27T17:07:37+00:00Added an answer on May 27, 2026 at 5:07 pm

    Well there is the selection sort, insertion sort, merge sort, quick sort, heap sort, etc. You can find a lot of information regarding the particular implementation around the web. If you want an easy way without regards to the actual implementation of the sorting algorithm, you can use std::sort to accomplish this.

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